Q:

PLEASE HELP ME!! D:Use the graph of the line to answer the questions.What is an equation of the line in point-slope form?How can the point-slope form be written in function notation?

Accepted Solution

A:
Answer:Point-slope form:[tex]y-0=\frac{1}{3} (x-1)\\f(x)-0=\frac{1}{3}(x-1)[/tex]Slope-intercept form:[tex]y=\frac{1}{3}x-\frac{1}{3} \\f(x)=\frac{1}{3} x-\frac{1}{3}[/tex]Step-by-step explanation:You have points on that line at (-2, -1) and (1, 0). To find your slope using those points, use the slope formula.[tex]\frac{y2-y1}{x2-x1} \\\\\frac{0-(-1)}{1-(-2)} \\\\\frac{0+1}{1+2} \\\\\frac{1}{3}[/tex]Now that we have your slope, you can use your slope and one of your points to write an equation in point-slope form.[tex]y-y1=m(x-x1)\\y-0=\frac{1}{3} (x-1)\\y=\frac{1}{3} x-\frac{1}{3}[/tex]To put it in function notation, substitute y for f(x).[tex]f(x)-0=\frac{1}{3} (x-1)\\f(x)=\frac{1}{3} x-\frac{1}{3}[/tex]